4n^2-30=14n

Solution for 4n^2-30=14n equation:

4n^2-30=14n

We move all terms to the left:

4n^2-30-(14n)=0

a = 4; b = -14; c = -30;
Δ = b2-4ac
Δ = -142-4·4·(-30)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-26}{2*4}=\frac{-12}{8}
=-1+1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+26}{2*4}=\frac{40}{8}
=5
$